0.3x^2=-3x

Solution for 0.3x^2=-3x equation:

0.3x^2=-3x

We move all terms to the left:

0.3x^2-(-3x)=0

We get rid of parentheses

0.3x^2+3x=0

a = 0.3; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·0.3·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*0.3}=\frac{-6}{0.6}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*0.3}=\frac{0}{0.6}
=0
$